KNN Project Exercise
Due to the simplicity of KNN for Classification, let's focus on using a PipeLine and a GridSearchCV tool, since these skills can be generalized for any model.
The Sonar Data
Detecting a Rock or a Mine
Sonar (sound navigation ranging) is a technique that uses sound propagation (usually underwater, as in submarine navigation) to navigate, communicate with or detect objects on or under the surface of the water, such as other vessels.

The data set contains the response metrics for 60 separate sonar frequencies sent out against a known mine field (and known rocks). These frequencies are then labeled with the known object they were beaming the sound at (either a rock or a mine).

Our main goal is to create a machine learning model capable of detecting the difference between a rock or a mine based on the response of the 60 separate sonar frequencies.
Data Source: https://archive.ics.uci.edu/ml/datasets/Connectionist+Bench+(Sonar,+Mines+vs.+Rocks)
Complete the Tasks in bold
TASK: Run the cells below to load the data.
# !pip install scikit-learnRequirement already satisfied: scikit-learn in /Users/drippy/.pyenv/versions/3.12.6/lib/python3.12/site-packages (1.7.2)
Requirement already satisfied: numpy>=1.22.0 in /Users/drippy/.pyenv/versions/3.12.6/lib/python3.12/site-packages (from scikit-learn) (2.2.5)
Requirement already satisfied: scipy>=1.8.0 in /Users/drippy/.pyenv/versions/3.12.6/lib/python3.12/site-packages (from scikit-learn) (1.15.2)
Requirement already satisfied: joblib>=1.2.0 in /Users/drippy/.pyenv/versions/3.12.6/lib/python3.12/site-packages (from scikit-learn) (1.5.2)
Requirement already satisfied: threadpoolctl>=3.1.0 in /Users/drippy/.pyenv/versions/3.12.6/lib/python3.12/site-packages (from scikit-learn) (3.6.0)3 more lines
[notice] A new release of pip is available: 25.1.1 -> 25.3
[notice] To update, run: pip install --upgrade pipdf = pd.read_csv('../DATA/sonar.all-data.csv')df.head()Freq_1
Freq_2
Freq_3
Freq_4
Freq_5127 more lines
Freq_6
Freq_7
Freq_8
Freq_9
Freq_10
...
Freq_52
Freq_53
Freq_54
Freq_55
Freq_56
Freq_57
Freq_58
Freq_59
Freq_60
Label
0
0.0200
0.0371
0.0428
0.0207
0.0954
0.0986
0.1539
0.1601
0.3109
0.2111
...
0.0027
0.0065
0.0159
0.0072
0.0167
0.0180
0.0084
0.0090
0.0032
R
1
0.0453
0.0523
0.0843
0.0689
0.1183
0.2583
0.2156
0.3481
0.3337
0.2872
...
0.0084
0.0089
0.0048
0.0094
0.0191
0.0140
0.0049
0.0052
0.0044
R
2
0.0262
0.0582
0.1099
0.1083
0.0974
0.2280
0.2431
0.3771
0.5598
0.6194
...
0.0232
0.0166
0.0095
0.0180
0.0244
0.0316
0.0164
0.0095
0.0078
R
3
0.0100
0.0171
0.0623
0.0205
0.0205
0.0368
0.1098
0.1276
0.0598
0.1264
...
0.0121
0.0036
0.0150
0.0085
0.0073
0.0050
0.0044
0.0040
0.0117
R
4
0.0762
0.0666
0.0481
0.0394
0.0590
0.0649
0.1209
0.2467
0.3564
0.4459
...
0.0031
0.0054
0.0105
0.0110
0.0015
0.0072
0.0048
0.0107
0.0094
R
5 rows × 61 columnsData Exploration
TASK: Create a heatmap of the correlation between the difference frequency responses.
# CODE HERE
plt.figure(figsize=(8,6))
sns.heatmap(df.select_dtypes(include='number').corr(), cmap='coolwarm')<Axes: >
TASK: What are the top 5 correlated frequencies with the target\label?
Note: You many need to map the label to 0s and 1s.
*Additional Note: We're looking for absolute correlation values.*
# create numeric target
df['Target'] = df['Label'].map({'R':0,'M':1})
# compute absolute correlations only on numeric columns and show the top 5 features (exclude Target itself)
corrs = df.select_dtypes(include='number').corr()['Target'].abs().sort_values(ascending=True)
top5 = corrs.drop('Target').tail(5)
top5Freq_45 0.339406
Freq_10 0.341142
Freq_49 0.351312
Freq_12 0.392245
Freq_11 0.4328551 more line
Name: Target, dtype: float64Train | Test Split
Our approach here will be one of using Cross Validation on 90% of the dataset, and then judging our results on a final test set of 10% to evaluate our model.
TASK: Split the data into features and labels, and then split into a training set and test set, with 90% for Cross-Validation training, and 10% for a final test set.
Note: The solution uses a random_state=42
from sklearn.model_selection import train_test_split
X = df.drop(['Label','Target'], axis=1)
y = df['Target']
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.3, random_state=101)TASK: Create a PipeLine that contains both a StandardScaler and a KNN model
from sklearn.preprocessing import StandardScaler
from sklearn.neighbors import KNeighborsClassifier
from sklearn.pipeline import Pipelinescalar = StandardScaler()
knn = KNeighborsClassifier()operations = [('scaler', scalar), ('knn', knn)]pipe = Pipeline(operations)TASK: Perform a grid-search with the pipeline to test various values of k and report back the best performing parameters.
from sklearn.model_selection import GridSearchCVk_values = list(range(1,20))
param_grid = {'knn__n_neighbors': k_values}full_cv_classifier = GridSearchCV(pipe, param_grid, cv=5, scoring='accuracy')
full_cv_classifier.fit(X_train, y_train)GridSearchCV(cv=5,
estimator=Pipeline(steps=[('scaler', StandardScaler()),
('knn', KNeighborsClassifier())]),
param_grid={'knn__n_neighbors': [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11,
12, 13, 14, 15, 16, 17, 18, 19]},54 more lines
scoring='accuracy')In a Jupyter environment, please rerun this cell to show the HTML representation or trust the notebook.
On GitHub, the HTML representation is unable to render, please try loading this page with nbviewer.org.
GridSearchCV
?Documentation for GridSearchCViFitted
Parameters
estimator
Pipeline(step...lassifier())])
param_grid
{'knn__n_neighbors': [1, 2, ...]}
scoring
'accuracy'
n_jobs
None
refit
True
cv
5
verbose
0
pre_dispatch
'2*n_jobs'
error_score
nan
return_train_score
False
best_estimator_: Pipeline
StandardScaler
?Documentation for StandardScaler
Parameters
copy
True
with_mean
True
with_std
True
KNeighborsClassifier
?Documentation for KNeighborsClassifier
Parameters
n_neighbors
2
weights
'uniform'
algorithm
'auto'
leaf_size
30
p
2
metric
'minkowski'
metric_params
None
n_jobs
None(HARD) TASK: Using the .cv_results_ dictionary, see if you can create a plot of the mean test scores per K value.
full_cv_classifier.cv_results_['mean_test_score']array([0.84137931, 0.84827586, 0.83448276, 0.8 , 0.77241379,
0.77931034, 0.73103448, 0.74482759, 0.71724138, 0.74482759,
0.72413793, 0.75862069, 0.71034483, 0.74482759, 0.72413793,
0.73103448, 0.70344828, 0.70344828, 0.70344828])plt.figure(figsize=(10,6), dpi=200)
plt.plot(k_values, full_cv_classifier.cv_results_['mean_test_score'], label='Mean Test Score')
plt.legend()
plt.xlabel('K Value')
plt.ylabel('Cross Validated Accuracy')Text(0, 0.5, 'Cross Validated Accuracy')
Final Model Evaluation
TASK: Using the grid classifier object from the previous step, get a final performance classification report and confusion matrix.
scaler = StandardScaler()
knn8 = KNeighborsClassifier(n_neighbors=8)
operations = [('scaler',scaler),('knn8',knn8)]pipe = Pipeline(operations)
pipe.fit(X_train,y_train)
pipe_pred = pipe.predict(X_test)from sklearn.metrics import classification_report
print(classification_report(y_test,pipe_pred)) precision recall f1-score support
0 0.82 0.70 0.75 33
1 0.71 0.83 0.77 30
3 more lines
accuracy 0.76 63
macro avg 0.77 0.77 0.76 63
weighted avg 0.77 0.76 0.76 63